/GM Christiansen 2515
| /GM Browne 2555
| | /GM Quinteros 2505
| | | /GM Seirawan 2555
| | | |
1 GM Andersson 2610 =1 1= 1= =1 | 6 / 8
2 GM Ljubojevic 2605 == 1= =1 == | 5 / 8
3 GM Larsen 2610 10 =0 10 11 | 4½/ 8
4 GM Portisch 2650 0= == 01 1= | 4 / 8
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4 3½ 3 2 |